Is anyone an electrical engineer or physics nerd help!

[Moonini 197]

Okay, so I have a circuit. I've previously solved said circuit but I have forgotten how! 

 

So I have the overall current of this circuit. 1.1 Amps, but I forgot how to solve parallel circuits specifically 10,15,20 Ohms here, I HAVE THE ANSWER BUT IDK

HOW THE FUCK I GOT IT

10 --> .5 Amps

15---> .33 Amps

20---> .25 Amps

 

Same for 30 & 35

30--> .59 Amps

35 --> .507 Amps   

If anyone knows how I got to these numbers I will greatly appreciate it. 

 

 

Dont fucking delete this milo

this has a faster response rate than chegg tbh

[HydraPOX 94]

https://en.wikipedia.org/wiki/Current_divider#

[Moonini 197]

20 minutes ago, HydraPOX said:

https://en.wikipedia.org/wiki/Current_divider#

this man solved it

he gave the equation to do so in steam

 

 

Everyone a round of applause for @ HydraPOX

[Doc 961]

Consider the following for parallel and series circuits: 

Series: 

• Total V = V1 + V2 + V3 (aka the total voltage is the sum of each part)
• Total A = A1 = A2 + A3 (aka the total current remains the same between each part)
• Total R = R1 + R2 + R3 (same as voltage)

Parallel: 

• Total V = V1 = V2 = V3
• Total A = A1 + A2 + A3
• 1 / Total R = 1/R1 + 1/R2 ...

Extra Formulas:
P=IV (aka Power = Current * Voltage)

V=IR (aka Voltage = Current * Resistance) 

 

For this specific circuit the parallel parts can be combined into one big part allowing the whole thing to be considered as a series circuit. 

Going clockwise from the power supply. 

1) R = 5

2) Combined Parallel Parts - 

Using resistance rules for parallel circuits we can determine that the total resistance is 1 / R = 1 / 10 + 1 / 15 + 1 / 20 thus R = 4.615

3) R = 25

4) Combine Parallel Parts - 

Same as 2 - 1 / R = 1 / 30 + 1/35 thus R = 16.154

5) R = 40 

 

Because we can combine the parallel parts into one big one and consider the whole circuit as a series we can determine the total resistance for the whole:

• R = 90.769

....

1 minute ago, Moonini said:

this man solved it

he gave the equation to do so in steam

 

 

Everyone a round of applause for @ HydraPOX

Welp I got too distracted with my league game so someone beat me to it lol

[HydraPOX 94]

2 minutes ago, Moonini said:

Everyone a round of applause for @ HydraPOX

Happy to be of service 

[Tman15tmb 1911]

Can someone point me to the retard area. I seemed to have stumbled into a room full of smart people.

[Mighty 1485]

6 hours ago, Doc said:

Consider the following for parallel and series circuits: 

Series: 

• Total V = V1 + V2 + V3 (aka the total voltage is the sum of each part)
• Total A = A1 = A2 + A3 (aka the total current remains the same between each part)
• Total R = R1 + R2 + R3 (same as voltage)

Parallel: 

• Total V = V1 = V2 = V3
• Total A = A1 + A2 + A3
• 1 / Total R = 1/R1 + 1/R2 ...

Extra Formulas:
P=IV (aka Power = Current * Voltage)

V=IR (aka Voltage = Current * Resistance) 

 

For this specific circuit the parallel parts can be combined into one big part allowing the whole thing to be considered as a series circuit. 

Going clockwise from the power supply. 

1) R = 5

2) Combined Parallel Parts - 

Using resistance rules for parallel circuits we can determine that the total resistance is 1 / R = 1 / 10 + 1 / 15 + 1 / 20 thus R = 4.615

3) R = 25

4) Combine Parallel Parts - 

Same as 2 - 1 / R = 1 / 30 + 1/35 thus R = 16.154

5) R = 40 

 

Because we can combine the parallel parts into one big one and consider the whole circuit as a series we can determine the total resistance for the whole:

• R = 90.769

....

Welp I got too distracted with my league game so someone beat me to it lol

[Goodideabadimplementation 109]

Delta v = I r 

[batGooseCan 641]

@ Ston3ColdK3iller